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Please, enter the prime modulus P: (better not greater than 350),
parameters a: and b: of equation Y² = X³ + aX + b (mod P).
Check this: if you want to see the lines with no zeros

Orders of solutions of equation Y² = X³ +X +1 (mod 13):

X \ Y	-6 = 7	-5 = 8	-4 = 9	-3 = 10	-2 = 11	-1 = 12	0	1	2	3	4	5	6	Y / X
0	.	.	.	.	.	6	.	6	.	.	.	.	.	0
1	.	.	18	.	.	.	.	.	.	.	18	.	.	1
2	.	.	.	.	.	.	.	.	.	.	.	.	.	2
3	.	.	.	.	.	.	.	.	.	.	.	.	.	3
4	.	.	.	.	9	.	.	.	9	.	.	.	.	4
5	.	.	.	.	.	18	.	18	.	.	.	.	.	5
6	.	.	.	.	.	.	.	.	.	.	.	.	.	6
7	.	.	.	.	.	.	2	.	.	.	.	.	.	7
8	.	.	.	.	.	9	.	9	.	.	.	.	.	8
9	.	.	.	.	.	.	.	.	.	.	.	.	.	9
10	3	.	.	.	.	.	.	.	.	.	.	.	3	10
11	.	.	.	.	9	.	.	.	9	.	.	.	.	11
12	.	18	.	.	.	.	.	.	.	.	.	18	.	12
X / Y	-6 = 7	-5 = 8	-4 = 9	-3 = 10	-2 = 11	-1 = 12	0	1	2	3	4	5	6	Y \ X

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Total quantity of finite solutions: 17

Max order of point is 18

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